Machine transcription
۱۴۸
مثال ٦ (لا+ی+ع)۳-لا۳-ی۳-ع۳=۳(لا+ی)(ی+ع)(ع+لا)
(لا+ی+ع)۳={لا+(ی+ع)}۳
=لا۳+۳لا۲(ی+ع)+۳لا(ی+ع)۲+(ی+ع)۳
=لا۳+۳لا۲(ی+ع)+۳لا(ی+ع)۲+{ی۳+۳ی۲ع+۳یع۲+ع۳}
=لا۳+ی۳+ع۳+۳(ی+ع){لا۲+لا(ی+ع)+یع}
=لا۳+ی۳+ع۳+۳(ی+ع){(لا+ی)(لا+ع)}
=لا۳+ی۳+ع۳+۳(لا+ی)(لا+ع)(ع+ی)
لهذا (لا+ی+ع)۳-لا۳-ی۳-ع۳={لا۳+ی۳+ع۳+۳(لا+ی)(لا+ع)
(ع+ی)}-لا۳-ی۳-ع۳
=۳(لا+ی)(ی+ع)(ع+لا)
مثال ۷ اگر ۲س=ا+ب+ج باشد ثابت کنید که
۲(س-ا)(س-ب)+۲(س-ب)(س-ج)+۲(س-ج)(س-ا)=۲س۲-ا۲-ب۲-ج۲
چون ۲لا+۲ی+۲ع=(لا+ی)+(ی+ع)+(ع+لا)
؞ ۲(س-ا)(س-ب)+۲(س-ب)(س-ج)+۲(س-ج)(س-ا)
={(س-ا)(س-ب)+(س-ب)(س-ج)}+{(س-ب)(س-ج)
+(س-ج)(س-ا)}+{(س-ج)(س-ا)+(س-ا)(س-ب)}
و چون (س-ا)(س-ب)+(س-ب)(س-ج)
=(س-ب){(س-ا)+(س-ج)}
=(س-ب){۲س-ا-ج}
=(س-ب)(ب)
Roughly two thirds of characters agree with a modern printed edition of the same text. Much of the disagreement is editorial, not misreading. Treat the transcription as a finding aid and read the page image before quoting. How this was measured.
